1 / 2A = 1 / 3B = 1 / 4C a + B + C = 18 find the value of a, B, C

Let 1 / 2A = 1 / 3B = 1 / 4C = K
Then: a = 2K; b = 3K; C = 4K
2k+3k+4k=18
9k=18
k=2
So:
a=2×2=4
b=2×3=6
c=2×4=8

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