[A-3] + [B + 4] + [C + 5] = 0, find 2A + 3b-4c

It's absolute
[a-3]+[b+4]+[c+5]=0
So A-3 = B + 4 = C + 5 = 0
a=3,b=-4,c=-5
So the original formula = 6-12 + 20 = 14

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