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Given the set a = {x │ - 1 ≤ x ≤ 2}, B = {y │ y = 2x-a, a ∈ R, X ∈ a}, C = {Z │ z = x & # 178;, X ∈ a} Is there a real number a so that C is included in B? If it exists, find out the value range of A. if it does not exist, explain the reason.
A={x|-1≤x≤2}
B={y|y=2x-a,a∈R,x∈A}={y|-2-a≤y≤4-a}
C={z|z=x²,x∈A}={z|0≤z≤4}
To include C in B
Then - 2-A ≤ 0, 4-A ≥ 4
So - 2 ≤ a ≤ 0
So there exists a value range of {a | - 2 ≤ a ≤ 0}
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