The limit of ((3x + 1) / (3 + x)) ^ (1 / (x-1)) when x tends to 1

Let f (x) = ((3x + 1) / (3 + x)) ^ (1 / (x-1)) ln f (x) = 1 / (x-1) * ln [(3x + 1) / (x + 3)] = 1 / (x-1) * ln [1 + 2 (x-1) / (x + 3)] when X - > 1, 2 (x-1) / (x + 3) - > 0, LN [1 + 2 (x-1) / (x + 3)] 2 (x-1) / (x + 3) LIM (x - > 1) LNF (x) = LIM (x - > 1

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1. If the equation of motion of a body is s = 7T ^ 2-13t + 8, then its instantaneous velocity at t = () is 1 Note: if the interval is | T, t + △ x |, then △ y = 7 △ x ^ 2 + 14T △ x + 7T ^ 2-13t-13 △ x + 8-7t ^ 2 + 13t-8 = 7 △ x ^ 2 + 14T △ x, then △ Y / △ x = 7 △ x + 14T, so 14T = 1, t = 1 / 14. But the answer is 1?
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