[（1-log6 3）²+log6 2×log6 18]/log6 4

[（1-log6 3）²+log6 2×log6 18]/log6 4

Let me separate them & nbsp; & nbsp; first of all, molecules & nbsp; [(1-log6 & nbsp; 3) ^ 2 + log6 & nbsp; 2 * log6 & nbsp; 18] = [(log6 & nbsp; 6-log6 & nbsp; 3) ^ 2 + log6 & nbsp; 2 * log6 & nbsp; 18] = [(log6 & nbsp; 2) ^ 2 + log6 & nbsp; 2 * log6 & nbsp; 18] = log6 & nbsp; 2 [log6 & nbsp; 2 + log6 & nbsp; 18] = (log6 & nbsp; 2) * 2log6 & nbsp; 6 = 2log6 & nbsp; 2
Denominator log6 & nbsp; 4 = 2log6 & nbsp; 2
So the reason why the original formula equals 1 is a little complicated. You can make do with it