Log12 (27) = a is known and log6 (16) is represented by A

Log12 (27) = a is known and log6 (16) is represented by A

a=ln(27)/ln(12)=3ln(3)/[2ln(2)+ln(3)]
2aln(2)=(3-a)ln(3)
ln(2)=ln(3)(3-a)/(2a)
log6(16)=ln(16)/ln6=4ln2/(ln2+ln3)
=4(3-a)/(2a)/[(3-a)/(2a)+1]
=4(3-a)/[(3-a)+2a]
=4(3-a)/(3+a)