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a=ln(27)/ln(12)=3ln(3)/[2ln(2)+ln(3)] 2aln(2)=(3-a)ln(3) ln(2)=ln(3)(3-a)/(2a) log6(16)=ln(16)/ln6=4ln2/(ln2+ln3) =4(3-a)/(2a)/[(3-a)/(2a)+1] =4(3-a)/[(3-a)+2a] =4(3-a)/(3+a)
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