已知log6(16)=a則log12(54)=(用a表示)

已知log6(16)=a則log12(54)=(用a表示)

log6(16)=log2(16)/log2(6)=4/log2(6)=alog2(6)=4/alog2(6)=log2(2*3)=log2(2)+log2(3)=1+log2(3)=4/alog2(3)=4/a-1log12(54)=log2(54)/log2(12)=[log2(6)+log2(3)+log2(3)]/[log2(2)+log2(6)] =(4/a+4/a-1+4/a-1/(…