There is a point in the angle ABC. Try to determine two points c and D on OA and OB to make the perimeter of triangle PCD shortest. Angle AOB = 30 degrees, Op = 10. Find the perimeter of triangle PCD

Let ∠ POA = θ, then ∠ POB = 30 ° - θ, make PM ⊥ OA intersect with OA at m, and extend PM by one time to e, i.e. me = PM. Make PN ⊥ ob intersect with OB at n, and extend PN by one time to F, i.e. NF = PN

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