If a and B satisfy that the square of a is multiplied by the square of B + the square of a + the square of B + 10ab + 16 = 0, find the square of a + the square of B

The square of a multiplied by the square of B + 8ab + 16 + the square of a + 2Ab + the square of B = 0
(ab+4)²+(a+b)²=0
∴ab+4=0
a+b=0
∴ab=-4 a+b=0
∴a²+b²=(a+b)²-2ab=0+8=8

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