There are some coal, a alone transport six days to complete, B alone transport five days to complete, now a transport three times, B transport two times, a total of 18 tons, the original total of how many tons?

Suppose a transports x tons every day, then B transports (18-3x) / 2 every day. Then according to the previous tips, we can get 6x = 5 * [(18-3x) / 2], and solve x = 10 / 3. So there are 20 tons

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