Given a 2 + B 2 + 2a-4b + 5 = 0, find the value of 2A 2 + 4b-3

∵ A2 + B2 + 2a-4b + 5 = 0, ∵ A2 + 2A + 1 + b2-4b + 4 = 0, namely (a + 1) 2 + (b-2) 2 = 0, ∵ a + 1) 2 = 0, (b-2) 2 = 0, namely a + 1 = 0, B-2 = 0, ∵ a = - 1, B = 2. ∵ 2A2 + 4b-3 = 2 + 8-3 = 7

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