First simplify, then evaluate 3A & sup2; B - [2Ab & sup2; - 2 (ab-3 / 2 A & sup2; b)] + 2Ab 3A & sup2; B - [2Ab & sup2; - 2 (ab-3 / 2 A & sup2; b)] + 2Ab. Where a and B satisfy │ B + 1 │ + (2a-4) & sup2; = 0 (detailed process is required)

First simplify, then evaluate 3A & sup2; B - [2Ab & sup2; - 2 (ab-3 / 2 A & sup2; b)] + 2Ab 3A & sup2; B - [2Ab & sup2; - 2 (ab-3 / 2 A & sup2; b)] + 2Ab. Where a and B satisfy │ B + 1 │ + (2a-4) & sup2; = 0 (detailed process is required)

It is reduced to: - 2A {(B-1 / 2) & sup2; - 5 / 4}
According to the satisfied conditions, we can get: B + 1 = 0; 2a-4 = 0. So B = - 1, a = 2
The answer is - 4