First simplify, then evaluate: (A-1) / a △ {a - (2a-1) / a}, where a = √ 3 + 1 First simplify, then evaluate: (A-1) / a △ {a - (2a-1) / a}, where a = √ 3 + 1

First simplify, then evaluate: (A-1) / a △ {a - (2a-1) / a}, where a = √ 3 + 1 First simplify, then evaluate: (A-1) / a △ {a - (2a-1) / a}, where a = √ 3 + 1

[(a-1)/a]÷[a-(2a-1)/a]
=[(a-1)/a]÷[(a²-2a+1)/a]
=[(a-1)/a]÷[(a-1)²/a]
=[(a-1)/a]×[a/(a-1)²]
=1/(a-1)
So, when a = √ 3 + 1, the original formula = 1 / [(√ 3 + 1) - 1] = 1 / √ 3 = √ 3 / 3