1. First simplify, then evaluate a - {b-2a + [3a-2 (B + 2a) + 5B]}, where a = 2009, B = 2010 2. Given X & sup2; + xy = 2, Y & sup2; + xy = 5, what is the value of 1 / 2x & sup2; + XY + 1 / 2Y & sup2? 3. If - 0.2A (3x power) B & sup3; and 1 / 2A & sup2; B (y power) are of the same kind, Find the value of the algebraic formula 3xy & sup2; - [2x & sup2; Y-2 (xy-3 / 2XY & sup2;) + XY] + 3x & sup2; y

1. First simplify, then evaluate a - {b-2a + [3a-2 (B + 2a) + 5B]}, where a = 2009, B = 2010 2. Given X & sup2; + xy = 2, Y & sup2; + xy = 5, what is the value of 1 / 2x & sup2; + XY + 1 / 2Y & sup2? 3. If - 0.2A (3x power) B & sup3; and 1 / 2A & sup2; B (y power) are of the same kind, Find the value of the algebraic formula 3xy & sup2; - [2x & sup2; Y-2 (xy-3 / 2XY & sup2;) + XY] + 3x & sup2; y

1. Simplification = a - {b-2a + [3a-2b-4a + 5B]}
=a-{4b-3a}
=4a-4b
Substituting a = 2009, B = 2010
Results = - 4
2. X & sup2; + xy = 2, Y & sup2; + xy = 5
x²+2xy+y²=5+2＝7
1/2x²+xy+1/2y²＝1/2（x²+2xy+y²）＝1/2×7＝7/2
3. According to the title: 3x = 2, y = 1, so x = 2 / 3, y = 1
3xy²-【2x²y-2（xy-3/2xy²）+xy】+3x²y
=3xy²-[2x²y-xy+3xy²]+3x²y
=x²y+xy
Substituting x = 2 / 3, y = 1
Results = 10 / 9