Given that the unit vector ABC is perpendicular to each other, simplify (2a-2b + 4C) times (- a-3b + 2C)
(2a-2b + 4C) times (- a-3b + 2C)
=-2a^2+6b^2+8c^2
Because AB, BC, CA are all 0
So there's nothing in the back
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