In △ ABC, if we know that the square of a = 1 / 3, the square of B = 1 / 4, then the angle B =?

In △ ABC, if we know that the square of a = 1 / 3, the square of B = 1 / 4, then the angle B =?

A = 1 / 3B = 1 / 4C, so B ^ 2 = 3A ^ 2, C ^ 2 = 4A ^ 2, that is, C ^ 2 = a ^ 2 + B ^ 2, so a triangle is a right triangle. Angle c = 90 degrees. SINB = B / C = radical 3 / 2, that is, angle B = 60 degrees