Known: A & # 178; + B & # 178; = 1, C & # 178; + D & # 178; = 1, AC + BD = 0, derived AB + BD = 0 Oh, it should be ab + CD = 0

Known: A & # 178; + B & # 178; = 1, C & # 178; + D & # 178; = 1, AC + BD = 0, derived AB + BD = 0 Oh, it should be ab + CD = 0

Just change the money
Let a = sin α, B = cos α, C = sin β, d = cos β
From AC + BD = 0, sin α sin β + cos α cos β = 0, that is cos (α - β) = 0, so α = π / 2 + β
SO 2 α = π + 2 β. Then sin (2 α) = - sin (2 β)
So sin (2 α) + sin (2 β) = 0
Then AB + CD = sin α cos α + sin β cos β = (1 / 2) · sin (2 α) + (1 / 2) · sin (2 β) = 0
ab+cd=0

Elden Ring Premiere

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