An object with a mass of 2kg falls without initial velocity and is subjected to air resistance which is directly proportional to the square of velocity (the coefficient of proportionality is k), Find the velocity expression of the object at any time T. (please use the differential equation solution)

An object with a mass of 2kg falls without initial velocity and is subjected to air resistance which is directly proportional to the square of velocity (the coefficient of proportionality is k), Find the velocity expression of the object at any time T. (please use the differential equation solution)

f=kv^2
a=g-f/m=g-kv^2/m
dv/dt=g-kv^2/m
1/(g-kv^2/m) dv=dt
The expressions of T and V can be obtained by dividing the area into two parts
Using the integral formula: ∫ 1 / (x ^ 2-A ^ 2) DX = (1 / 2a) ln [(x-a) / (x + a)] + C