The initial velocity of an object moving in a straight line with uniform velocity is 12 m / s, and the displacement in the sixth second is 4 m more than that in the fifth second. When the object moves from point a of 14 m to point B of 32 m, it takes 1 s, right? Why?

The results show that the displacement in 6S and 5S is x and X 'respectively, and the instantaneous velocity in the middle of - segment displacement is equal to the average velocity of this segment displacement, T1 is the instantaneous velocity of 4.5s, V1 = x' / 1 = x't2 is the instantaneous velocity of 5.5s, V2 = x / 1 = x'a = (v2-v1) / (t2-t1) = (x-x ') / (5.5-4.5) = 4m / S ^ 2 is set in a, B

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1. The initial velocity of the object moving in a straight line with uniform velocity is 12 m / s, and the displacement in the sixth second is 4 m more than that in the fifth The time taken for an object to move from point a of 14m to point B of 32m is 1s. Why is that right? Why do I calculate that there is only 14m displacement in one second
2. The initial velocity of an object moving in a straight line with uniform velocity is 28m / s, and the displacement in the 6S is 4m less than that in the 5S If the initial velocity of an object moving in a straight line with uniform velocity is 28m / s, the displacement in the 6S is 4m less than that in the 5S, what is the acceleration of the object?
3. When an object moves in a straight line with uniform acceleration, the displacement is 10m in the fifth second and 20m in the seventh second,
4. When an object moves in a straight line with uniform acceleration, the displacement is 10 m in the third second and 14 m in the fifth second, Here is my process 1/2a+V0=10 1 1/2a+V0'=14 2 Here, V0 refers to the velocity at the end of the second second second, and V0 'refers to the velocity at the end of the fourth second 1-2 to get V0 '- V0 = 4 So a = 2m / S ^ 2 Then 1 / 2 × 2 + V0 = 10 So the initial velocity is 8m / s But the initial speed in the answer is 5m / s, which I don't understand. I hope you can analyze the problems in my process,
5. If the average velocity from the end of 5S to the end of 9s is 2.1mgs, Such as the title
6. For a particle moving in a straight line with uniform velocity, the initial velocity is 0.5m/s, and the displacement in the 9th second is 4m more than that in the 5th second? (2) What is the displacement of the particle passing through in 9s?
7. The initial velocity of a particle moving in a straight line with uniform velocity is 0.5m/s, which is higher in the 9th s than in the 5th s
8. If the average velocity of the particle moving from the end of 5S to the end of 19S is 3.6m/s, the displacement of the particle in the first 8s can be calculated by the proportional method
9. For a particle moving in a straight line with uniform velocity, the initial velocity is 0.5m/s, and the displacement in the 9th second is 4m more than that in the 5th second? (2) What is the displacement of the particle passing through in 9s?
10. The average velocity in the first second is 1.2 m / s, and the average velocity in the second second is 1 m / s. The acceleration and total displacement of an object are calculated
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14. When the car runs at a uniform speed of 10m / s and gets an acceleration of 2m / S2 after braking to make a uniform deceleration movement, how many meters is the displacement within 8s after braking?
15. 1. For an object moving in a straight line with uniform acceleration, if the initial velocity is 2m / s and the displacement it passes through in the third second is 4, then its acceleration is?
16. What is the initial velocity of an object moving uniformly in a straight line with an acceleration of 2m / s, and its displacement in the second second second is 12m? What's the speed at the end of the 4th second? Please explain in detail
17. If the acceleration of the object is 2m / S ^ 2, the displacement in the first second is 2m, then the displacement in the third second
18. For an object moving in a straight line with uniform acceleration, the acceleration is 2m / S2, which means () A. The speed of an object at the end of any second is twice that at the beginning of that second. B. the speed of an object at the end of any second is 2 m / s higher than that at the beginning of that second. C. the speed of an object at the end of the first second is 2 m / s. D. the initial speed of an object in any second is 2 m / s higher than that at the end of the previous second
19. If the acceleration of the object is known to be 2m / s and 178;, then in any 1s A. The final velocity of an object must be twice the initial velocity The final velocity of object B must be 2m / s higher than the initial velocity in the first 1s The initial velocity of Object C must be 2m / s higher than the final velocity in the first second The final velocity of object d must be 2m / s higher than the initial velocity Why do you choose D? I'm going to have an exam tomorrow
20. If the acceleration is known to be 2m / S2, then () A. The speed of an object at the end of a certain one second must be twice as fast as that at the beginning of that second. B. the speed of an object at the end of a certain one second must be 2m / SC higher than that at the beginning of that second. The speed of an object at the beginning of a certain one second must be 2m / SD higher than that at the end of the previous second. The speed increase of an object per second is 2m / s