For a particle moving in a straight line with uniform velocity, the initial velocity is 0.5m/s, and the displacement in the 9th second is 4m more than that in the 5th second? (2) What is the displacement of the particle passing through in 9s?

According to the fact that the difference of displacement in continuous equal time is a constant quantity, X ′ 9 − x ′ 5 = 4at2, the solution is a = x ′ 9 − x ′ 54t2 = 44 × 12m / S2 = 1m / S2. The displacement in 9s is x = v0t + 12at2 = 0.5 × 9 + 12 × 1 × 92m = 45m

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