The initial velocity of an object moving in a straight line with uniform velocity is 28m / s, and the displacement in the 6S is 4m less than that in the 5S If the initial velocity of an object moving in a straight line with uniform velocity is 28m / s, the displacement in the 6S is 4m less than that in the 5S, what is the acceleration of the object?

The initial velocity of an object moving in a straight line with uniform velocity is 28m / s, and the displacement in the 6S is 4m less than that in the 5S If the initial velocity of an object moving in a straight line with uniform velocity is 28m / s, the displacement in the 6S is 4m less than that in the 5S, what is the acceleration of the object?

If the displacement in the 6S is 4m less than that in the 5S, the velocity in this second is reduced by 4m / s, and the acceleration of the object is - 4m / S2 (- 4m per second)
Check it, the displacement in the fourth second is 28m / s * 4 + 1 / 2 * (- 4) * (4 * 4) = 80m, the displacement in the fifth second is 28m / s * 5 + 1 / 2 * (- 4) * (5 * 5) = 90m, the displacement in this second is 90m-80m = 10m; the displacement in the sixth second is 28m / s * 6 + 1 / 2 * (- 4) * (6 * 6) = 96m, the displacement in this second is 96m-90m = 6m, that is, the displacement in the sixth second is 10m-6m = 4m less than that in the fifth second, which is consistent with the original problem