When the speed of the car is 18m / s, the car makes a uniform deceleration linear motion after the emergency brake, and the acceleration is 6m / S2. The distance of the car passing through in 6S after the brake is calculated

It takes t = vt − v0a & nbsp; & nbsp; that is: T = 0 − 18m / s − 6m / S2 = 3S ＜ 6S. The car stops within 3S when it starts to move. Therefore, the distance passed within 6S is the distance passed within 3S. S = v0t + 12at2 & nbsp; that is: S = 18 × 3 + 12 × (− 6) × 32 = 27m. A: the distance passed within 6S after braking is 27m

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