The object slides on the smooth slope at the speed of 4m / s, passing through two points a and B. the speed at point a is twice that at point B. from point B to the top C of the slope after 0.5s, the speed becomes 0, as shown in the figure. The distance between a and B is 0.75m. Try to find the length of the slope and the time it takes for the object to slide from the bottom d to B? (the object moves in a straight line with uniform deceleration on the inclined plane)

Let the velocity of point a be VA, the velocity of point B be VB, the acceleration be a, and the length of slope be s. A to B: vb2-va2 = 2asab ①vA=2vB … ② B to C: 0 = VB + at0 ③ Solution (1) (2) (3) is: VB = 1m / s, a = - 2m / S2D to C: 0-v02 = 2As ④ When s = 4m from D to B

RELATED INFORMATIONS

1. When an object moves in a straight line with uniform deceleration V0 = 3m / s a = 0.4m/s ^ 2 the displacement of the object in a certain 1s s = 0.4m how long has the object been moving before this 1s?
2. When the speed of the car is 18m / s, the car makes a uniform deceleration linear motion after the emergency brake, and the acceleration is 6m / S2. The distance of the car passing through in 6S after the brake is calculated
3. If there is an object moving in a straight line with uniform acceleration and zero initial velocity, and the acceleration is 3m / S ^ 2, then: What is the difference between the displacements of two adjacent ones within 1 s? How to calculate the displacement ratio in the first second, the second and the third seconds? How to calculate the ratio of the average speed in the first second, the second and the third seconds? How to calculate the ratio of initial velocity at the end of 1s, 2S and 3S?
4. When the acceleration is 3m / S2, then () A. The end velocity of a second must be 3 times of the initial velocity of that second. B. the initial velocity of a second must be 3 M / s higher than that of the previous second. C. the end velocity of a second must be 3 M / s higher than that of the previous second. D. the end velocity of a second must be 3 M / s higher than that of the previous second
5. A and B start from the same ground and direction at the same time. A moves in a straight line at a uniform speed of 6m / s. B starts from a standstill and moves in a straight line at a uniform acceleration of 3m / S2 How long does it take before B overtakes a? What is the distance between the two cars? (2) When does car B catch up with car a? What's the speed of car B at this time?
6. If the acceleration of an object moving in a straight line at a constant speed is 3m / s, is the velocity at the end of a 1s always 3m / s higher than that at the beginning of the 1s?
7. When the acceleration of an object moving in a uniform straight line is 3 M / s and reaches 15 m / s after 4 S, / degree, the initial velocity of the object will decrease
8. The cyclist rides on a 30 m long slope with an initial speed of 5 m / S2 per second, and the acceleration is 0.4 m / S2 Q: 1. How fast does the bicycle reach the top of the slope? 2. What is the displacement in the second second?
9. 2. The cyclist starts to go downhill at a speed of 3 M / s, and gains an acceleration of 8 cm / S 2 on the downhill road. The speed and displacement of the cyclist at 10 s after going downhill are calculated
10. Someone rides a bicycle at an initial speed of 4 meters per second and drives up a slope with an acceleration of 0.2 meters per square second and a slope length of 20 meters, How long does it take for a bicycle to cross the slope?
11. For a particle moving in a straight line with uniform velocity, the initial velocity is 0.5m/s, and the displacement in the 9th second is 4m more than that in the 5th second? (2) What is the displacement of the particle passing through in 9s?
12. A physics problem in grade one of senior high school When a train starts to move in a straight line with uniform acceleration from static state, an observer stands at the front end of the first carriage. He measures that it takes 10 seconds for the first carriage to pass through him, and it takes 30 seconds for all trains to pass through him. Assuming that each carriage is equal in length, the total number of trains is
13. In the first 10 seconds, the object moves forward 10 meters 1. What are the displacements in the last 10 seconds and the 10th? 2. What is the average velocity in the first six seconds and the sixth?
14. When car a runs at 20m / s, the driver finds that car B runs at 10m / s in the same direction at 500m ahead on the same straight road. In order to avoid collision, the driver of car a immediately brakes, and calculates the minimum value of a when the driver of car a brakes
15. On the problem of uniform variable speed motion in senior one physics The initial speed of the bicycle is 4 m / s, the acceleration is 0.2 M / s, and the total travel time is 20 m
16. The car starts at an acceleration of 1 m / s, and at the same time, one person is willing to catch up with the car at a speed of V0 60 m behind the car to stop the car (1) At least how big is V0? (2) If the speed of V0 = 10m / s, what is the minimum distance between people and vehicles? I hope you will explain how to do it, Don't just write the results
17. Physics problems in grade one of senior high school 6. When a, B and C move at a constant speed, the velocity of a is 6m / s and the acceleration is 1m / S2; the velocity of B is 2m / s and the acceleration is 6m / S2; the velocity of C is - 4m / s and the acceleration is 2m / S2 A. When passing through point a, object a is the fastest and object B is the slowest B. The object C is the fastest and the object B is the slowest when it passes l s before point a C. One second after passing point a, object B is the fastest and Object C is the slowest D. None of the above is true The answer is ABC, why? The analysis says that the velocity of a is 5m / s in the second before passing through point a, and it is 7m / s in the second after passing through point A. is it the law of decreasing in the second before and increasing in the second after?
18. Uniform variable speed motion of physics in grade one of senior high school The motorcycle starts at rest, makes a uniform acceleration linear motion with the acceleration of A1 = 2m / S ^ 2, makes a uniform speed linear motion in the middle, and then makes a uniform deceleration linear motion with the acceleration of A2 = 4m / S ^ 2 until it stops. The total displacement is 1.8km. The duration t = 60s, and the solution is as follows (1) The maximum speed of a car in motion (2) When the acceleration of acceleration and deceleration process is the same as the original, and finally just stationary, the shortest time needed to walk this displacement and the maximum speed of getting off the car in this case (2) Because the time is the shortest, the time of uniform motion should be 0 Let v be the maximum speed v/2*v/2+v/4*v/2=1800 V = 40 root sign 3 The time is v / 2 * 1.5 = 30 root sign 3 The above is an answer from the Internet, I can't understand the formula of the second question, please explain!
19. When an object starts to move in a straight line with a constant acceleration of 0.5m/s ^ 2 from rest, and then decelerates for 6m to rest, if the time taken in the whole process of the object's motion is 10s, the following formula can be obtained: (1) The maximum speed of an object (2) The acceleration of an object during deceleration
20. When a cloud with initial velocity of 6m / s and acceleration of - 1 decelerates and moves in a straight line, the displacement of the object passing through in the second is 0.5m