The car starts at an acceleration of 1 m / s, and at the same time, one person is willing to catch up with the car at a speed of V0 60 m behind the car to stop the car (1) At least how big is V0? (2) If the speed of V0 = 10m / s, what is the minimum distance between people and vehicles? I hope you will explain how to do it, Don't just write the results

The car starts at an acceleration of 1 m / s, and at the same time, one person is willing to catch up with the car at a speed of V0 60 m behind the car to stop the car (1) At least how big is V0? (2) If the speed of V0 = 10m / s, what is the minimum distance between people and vehicles? I hope you will explain how to do it, Don't just write the results

When the distance from the car is less than 20m and the duration is 2S, the information can be transmitted to the driver. After the time t, the distance between the person and the car is 20m, i.e. 1 / 2at2 + 60 VOT = 20. At this time, the speed is at. In the next 2S, keep the distance of 20m, i.e. the square of 2 * VO = at * 2 + 1 / 2A * 2