When an object is accelerating uniformly, its initial velocity is 2 m / s, and its displacement in the third second is 4.5 m, the acceleration is calculated

The third second displacement is equal to the first three seconds displacement minus the first two seconds displacement
We can get: (v0t3 + 1 / 2at3 ^ 2) - (v0t2 + 1 / 2at2 ^ 2) = Δ X
Substituting the data, we can get: (2 × 3 + 1 / 2A × 3 ^ 2) - (2 × 2 + 1 / 2A × 2 ^ 2) = 4.5
The solution is: a = 1m / S ^ 2

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