The initial velocity of the object is 5m / s, and the acceleration is - 2m / S ^ 2 What is the distance in 4 seconds if you slide on a rough horizontal surface? Is the object moving in the direction of acceleration to the left or deceleration to the right

The initial velocity of the object is 5m / s, and the acceleration is - 2m / S ^ 2 What is the distance in 4 seconds if you slide on a rough horizontal surface? Is the object moving in the direction of acceleration to the left or deceleration to the right

5=2*2.5s
So let the original direction of motion be right
In the first 2.5 seconds
After 2.5s, the speed is 0
Let the right be the positive direction
Then s = 5 * T-1 / 2 * a * T ^ 2 = 5 * 2.5-6.25 = 6.25m
Do you understand