1. First simplify, then evaluate [(3x + 4Y) ^ 2 - 3x (3x + 4Y)] / (- 6y), where x = - 1, y = 3
[(3X+4Y)^2 -3X(3X+4Y)]÷(-6Y)
=(3X+4Y)(3X+4Y-3X)÷(-6Y)
=-2/3(3X+4Y)
Where x = - 1, y = 3
-2/3(3X+4Y)
=-2/3(-3+12)
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