The value range of real number m is the equation x ^ + (m-1) x + 2m + 6 = 0 Find the range of the real number m so that the equation x ^ 2 + 2 (m-1) x + 2m + 6 = 0, (1) There are two real roots, one is greater than 2 and the other is less than 2; (2) Both solid roots are larger than 1; (3) Two real roots x1, X2 satisfy 0

The value range of real number m is the equation x ^ + (m-1) x + 2m + 6 = 0 Find the range of the real number m so that the equation x ^ 2 + 2 (m-1) x + 2m + 6 = 0, (1) There are two real roots, one is greater than 2 and the other is less than 2; (2) Both solid roots are larger than 1; (3) Two real roots x1, X2 satisfy 0

You write x1 × X2, X1 + X2, and then look
First, two real roots, DET > = 0, M > = 5 or m2, are substituted into 1, and the equation is greater than zero
3. Similarly, substitute 0, 1, 4 and draw a picture