When the moving point a moves on the circle x2 + y2 = 1, the trajectory equation of the midpoint of its line with the fixed point B (3,0) is () A. (x+3)2+y2=4B. (x-3)2+y2=1C. (2x-3)2+4y2=1D. (x+3)2+y2=12

When the moving point a moves on the circle x2 + y2 = 1, the trajectory equation of the midpoint of its line with the fixed point B (3,0) is () A. (x+3)2+y2=4B. (x-3)2+y2=1C. (2x-3)2+4y2=1D. (x+3)2+y2=12

Let the midpoint m (x, y), then the moving points a (2x-3, 2Y), ∵ a are on the circle x2 + y2 = 1, ∵ (2x-3) 2 + (2Y) 2 = 1, that is, (2x-3) 2 + 4y2 = 1