動點A在圓x2+y2=1上移動時,它與定點B(3,0)連線的中點的軌跡方程是() A.(x+3)2+y2=4B.(x-3)2+y2=1C.(2x-3)2+4y2=1D.(x+3)2+y2=12

動點A在圓x2+y2=1上移動時,它與定點B(3,0)連線的中點的軌跡方程是() A.(x+3)2+y2=4B.(x-3)2+y2=1C.(2x-3)2+4y2=1D.(x+3)2+y2=12

設中點M(x,y),則動點A(2x-3,2y),∵A在圓x2+y2=1上,∴(2x-3)2+(2y)2=1,即(2x-3)2+4y2=1.故選C.