When a moving point P moves on the circle x 2 + y 2 = 1, the trajectory equation of the midpoint m connecting it with the fixed point a (3,0) is obtained
Take any point B (m, n) on the circle x2 + y2 = 1, and let the midpoint m (x, y) of line AB have x = 3 + M2y = 0 + N2, that is, M = 2x-3n = 2Y. According to M2 + N2 = 1, we can get (x-32) 2 + y2 = 14, that is, the trajectory equation of midpoint m is (x-32) 2 + y2 = 14
RELATED INFORMATIONS
- 1. When the moving point a moves on the circle x2 + y2 = 1, the trajectory equation of the midpoint of its line with the fixed point B (3,0) is () A. (x+3)2+y2=4B. (x-3)2+y2=1C. (2x-3)2+4y2=1D. (x+3)2+y2=12
- 2. Application of circle and equation The chord length of line L: 2x-y-2 = 0 cut by circle C: (x-3) & sup2; + Y & sup2; = 9
- 3. The equation of line and circle in high school mathematics In a triangle, the opposite sides of angle a, angle B and angle c are known to be a, B and C respectively, and a > C > b is an arithmetic sequence, | ab | = 2. The trajectory equation of the vertex is obtained
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- 11. When the moving point a moves on the circle x2 + y2 = 1, the trajectory equation of the midpoint of its line with the fixed point B (3,0) is () A. (x+3)2+y2=4B. (x-3)2+y2=1C. (2x-3)2+4y2=1D. (x+3)2+y2=12
- 12. When the moving point a moves on the circle x2 + y2 = 1, the trajectory equation of the midpoint of its line with the fixed point B (3,0) is () A. (x+3)2+y2=4B. (x-3)2+y2=1C. (2x-3)2+4y2=1D. (x+3)2+y2=12
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