Given that the point P is a moving point on the curve y = x & sup2;, q (4,0), then the trajectory equation of the midpoint of the line PQ is?

Let the coordinates of point m be m (x, y)
Because m is the midpoint of P and Q, the coordinates of P are (2x-4,2y)
P is on y = x & sup2;, so:
2y=(2x-4)²=4x²-16x+16
The trajectory equation of the midpoint m is y = 2x & sup2; - 8x + 8

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