It is known that LG2 = A and Lg3 = B. try to use a and B to represent log125
Bottom changing formula: log12 5 = lg5 / LG12
lg5=lg(10/2)=lg10-lg2=1-a
lg12=lg(2²×3)=2lg2+lg3=2a+b
The original formula = (1-A) / (2a + b)
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