(lgx) ^ 2 + (LG2 + Lg3) lgx + LG2. Lg3 = 0, if two are x1.x2, then x1x2 =? Use the method of setting unknowns

Another lgx = t
The original formula is T ^ 2 + (LG2 + Lg3) t + LG2 * Lg3 = 0
The cross multiplication is used to get (T + LG2) * (T + Lg3) = 0
T1 = - LG2 or T2 = - Lg3
Lgx = - LG2 or lgx = - Lg3
So X1 = 1 / 2, X2 = 1 / 3
So x1x2 = 1 / 6

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