Given 〡 X-2 〡 + (3-y) ² = 0, find the values of the following formulas, (1) the square of y of X, (2) xy-xy of X

Because X has absolute value and y has square, so 〡 X-2 〡 = 0, (3-y) ² = 0
x=2,y=3
Substituting x = 2 and y = 3
Original formula = 2 & # 179; = 8
Original formula = 2 / (2 * 3) - (2 * 3)
=1/3-6
=-17/3

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