If the remainder of polynomial x ^ 5 + 3x ^ 4 + 8x ^ 3 + 11x + m divided by X + 2 is 1, then the value of M is ()

x^5+3x^4+8x^3+11x+m
=(x^5+2x^4)+(x^4+2x^3)+(6x^3+12x^2)-(12x^2+24x)+(35x+70)+(m-70)
=x4(x+2)+x^3(x+2)+6x^2(x+2)-12x(x+2)+35(x+2)+m-70
Therefore, for a polynomial to be divisible by X + 2, we need m-70 = 1
=>m=71

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