If a and B are fixed values, the solution of the linear equation of one variable (2kA / 3) - (x-bx / 6) = 2, no matter what the value of K is X = 1, find the value of a and B I saw that other people didn't explain why ∵ K is any value ∴4a=0 13-b=0?
You can make it x =
Then, because when k is any value, X is 1
So a must be equal to 0
The solution is b = 18 and a = 0
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