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If a and B are fixed values, the solution of the equation (3kx + a) / 3 - (x-bx) / 6 = 2 is always 1 no matter what the value of K is
The constant solution of the equation (3kx + a) / 3 - (x-bx) / 6 = 2 is 1, that is to say, substituting x = 1, the equation can also become immediately (3K + a) / 3 - (1-B) / 6 = 22 (3K + a) - (1-B) = 126k + 2a-1 + B = 1213-2a-b = 6k2a + B = 13-6k. Because a is a fixed value, B is a fixed value, so 2A + B is a fixed value, so 13-6k must be a fixed value
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