How to solve the linear equation of one variable with fractional denominator For example: 0.3x/0.4-0.5x/0.6 = 8 I've given a blind example, which is mainly "=" do you want to multiply the right side by the same value as the left side?

Both sides of the equation are multiplied by the same number (nonzero) or divided by the same number (nonzero)

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1. If the denominator of a linear equation with one variable is the same, what should we do? For example, 80 (X-5) - 2 = 80 (x + 1) + 2 Where - 2 and + 2 are not molecules, but numbers added to fractions If the denominator is multiplied by 80, are the - 2 and + 2 after the fraction still multiplied 80 / (X-5) (the whole of a fraction) is followed by - 2, 80 / (x + 1) (the whole of a fraction) is followed by + 2 -2 and + 2 are not one with 80 (X-5) and 80 (x + 1)
2. I'd like you to give me 20 formulas for the equation of first degree with one variable to the denominator
3. How to solve the linear equation with denominator
4. Write an equation of first degree with one variable containing at least three terms so that its solution is x = 3
5. Please write a linear equation of one variable whose solution is x = 2 and the coefficient of X is 3
6. Please write a linear equation of one variable whose solution is x = 2 and the coefficient of X is 3______ ．
7. Write a linear equation of one variable with x = 3 as solution______ (fill in only one equation satisfying the condition)
8. Write a linear equation with one variable so that its solution is - 3
9. Write a linear equation of one variable with x = 2 as the solution and the coefficient of an unknown is 0.5
10. Write a linear equation of one variable about X, and make its solution 3, the coefficient of x 3 / 2
11. If a and B are fixed values, the solution of the linear equation 2kA + x3-x-bx6 = 2 is always 1 no matter what the value of K is
12. If a and B are fixed values, the solution of the equation (3kx + a) / 3 - (x-bx) / 6 = 2 is always 1 no matter what the value of K is
13. If a and B are fixed values, the solution of the linear equation of one variable (2kA / 3) - (x-bx / 6) = 2, no matter what the value of K is X = 1, find the value of a and B I saw that other people didn't explain why ∵ K is any value ∴4a＝0 13-b＝0?
14. If a and B are fixed values, 2kx + A / 3 - x-6k / 6 = 2, no matter what the value of K is, his solution is always 1, and the value of a and B is obtained
15. It is known that a and B are fixed values. No matter what the value of K is, the solution of the linear equation (3kx + A / 3) - (x-6k / 6) = 2 with respect to X is always x = 1 Try to find the value of a and B The equation is [(3kx + a) / 3] - [(x-bk) / 6] = 2
16. The denominator in the equation x0.7 − 0.17 − 0.2x0.03 = 1 is changed into an integer, and the correct one is () A. x7−17−2x3＝1B. 10x7−17−2x3＝1C. 10x7−17−20x3＝10D. 10x7−17−20x3＝1
17. 0.7/x-0.03 / (0.17-0.2x) = 1 (find x,)
18. If x = 1, the value of the algebraic formula ax ^ 2 + BX + 1 is 5. When x = - 1, the value of the algebraic formula ax ^ 3 + BX + 1 is obtained The first is ax ^ 2, the second is ax ^ 3
19. When x = 1 and x = - 4, the value of the algebraic formula ax ^ 2 + BX + C is 8. When x = - 1, the value of the algebraic formula ax ^ 2 + BX + C is 2. Find the value of a, B and C
20. If 2x + 3Y = 4, try to find the value of the power X of the algebraic formula 4 and the power y of the algebraic formula 8