The square of (x-3) (2-x) (x + 1) (x + 2x + 4) is less than or equal to 0

The square of (x-3) (2-x) (x + 1) (x + 2x + 4) is less than or equal to 0

The square of X + 2x + 4 > 0, and the square of 2-x ≥ 0
When x = 2, the square of (x-3) (2-x) (x + 1) (x + 2x + 4) is less than or equal to 0
When x ≠ 2, the square of (2-x) is greater than 0
If the square of (x-3) (2-x) (x + 1) (x + 2x + 4) is less than or equal to 0, it becomes
(x-3)(X+1)≤0
The solution is - 1 ≤ x ≤ 3
The solution of (x-3) (2-x) (x + 1) (x + 2x + 4) less than or equal to 0 is [- 1,3]