Known: x2 + Y2 + 6x-4y + 13 = 0. Find the value of (x + y) 2008

∵ x2 + Y2 + 6x-4y + 13 = 0, ∵ (x + 3) 2 + (Y-2) 2 = 0, the solution is: x = - 3, y = 2, ∵ (x + y) 2008 = 1

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