How to solve the equation x + 1 / 2 + 1 / x = the square of X + 32 / 2x It's 15 in the end

X + 1 / 2 + 1 / x = square of X + 32 / 2x
1/(x+2)+1/x=32/(x²+2x);
(x+x+2)/x(x+2)=32/x(x+2);
2x+2=32;
2x=30;
x=15;
Bring in test is not root adding;
So x = 15;
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