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Given (quadratic power of a + quadratic power of B) * (quadratic power of a + quadratic power of B-8) + 16 = 0, find the value of (quadratic power of a + quadratic power of B)
(quadratic power of a + quadratic power of B) * (quadratic power of a + quadratic power of B-8) + 16 = 0
Let a and#178; + B and#178; = X,
Then the original equation can be reduced to
x(x-8)+16=0
∴x²-8x+16=0
(x-4)²=0
∴x=4
That is, a & # 178; + B & # 178; = 4
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