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(a的二次方+b的二次方)*(a的二次方+b的二次方-8)+16=0 設a²;+b²;=x, 則原方程可化為 x(x-8)+16=0 ∴x²;-8x+16=0 (x-4)²;=0 ∴x=4 即a²;+b²;=4
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