It is known that the set M = {f (x) | has a real number x0 in the domain, such that f (x0 + 1) = f (x0) + F (1) holds} Let f (x) = in (A / 2 ^ x + 1) ∈ m, find the value range of real number a PS: it's a / (2 ^ x) and then add 1 to the equation as a whole

It is known that the set M = {f (x) | has a real number x0 in the domain, such that f (x0 + 1) = f (x0) + F (1) holds} Let f (x) = in (A / 2 ^ x + 1) ∈ m, find the value range of real number a PS: it's a / (2 ^ x) and then add 1 to the equation as a whole

If we take both sides of the function and simplify it at the same time, we can get that if f (x0 + 1) = f (x0) + F (1) holds, there must be a + A ^ 2 + A * (2 ^ x) = 0. When a = 0, for any x ∈ m, when a is not equal to 0, a = - 1-2 ^ x, and the truth part is greater than 0, that is, a > - 2 ^ x, we can see that such a does not exist, because a = 0