Given that the quadratic power of A-6A + 9 and / B-1 / are opposite to each other, what is the result of calculating the cubic power of a, the cubic power of B + the quadratic power of 2a and the quadratic power of B + AB

(a ^ - 6A + 9) + | B-1 | = 0 (^ for square, ^ 3 for cubic)
(a-3)^+|b-1|=0
a=3,b=1
a^3b^3+2a^b^+ab=ab(ab+1)^=3(3+1)^=48

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