If the square of a + the square of B + the square of C - AB BC AC = 0, try to explore the size relationship between ABC
a²+b²+c²-ab-bc-ca=0
2a²+2b²+2c²-2ab-2bc-2ca=0
a²-2ab+b²+b²-2bc+c²+c²-2ac+a²=0
(a-b)²+(b-c)²+(c-a)²=0
∴a-b=0
b-c=0
c-a=0
∴a=b,b=c,c=a
∴a=b=c
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