It is known that plane α and β satisfy α⊥ β, α∩ β = L, straight line AB is in plane α, ab ⊥ L, straight line BC and de are in plane β, and BC ⊥ de. the proof is AC ⊥ De
It is proved that: plane α and β satisfy α ⊥ β, α ∩ β = L, straight line AB is in plane α, ab ⊥ L, ∩ ab ⊥ β, ≁ straight line BC and de are in plane β, and BC ⊥ De, ∩ ab ⊥ BC = B, ∩ de ⊥ plane ABC, ⊂ AC ⊂ plane ABC, ⊥ AC ⊥ De
RELATED INFORMATIONS
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- 3. It is known that a + B + C = 2,0
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