In △ ABC. Ab ⊥ AC, ad ⊥ BC in D, the proof: 1 / ad ^ 2 = 1 / AB ^ 2 + 1 / AC ^ 2 So in the tetrahedral ABCD, what kind of conjecture can you get by analogy with the above conclusion, and explain the reason

In △ ABC. Ab ⊥ AC, ad ⊥ BC in D, the proof: 1 / ad ^ 2 = 1 / AB ^ 2 + 1 / AC ^ 2 So in the tetrahedral ABCD, what kind of conjecture can you get by analogy with the above conclusion, and explain the reason

Bcxad = abxac (equal triangle area)
1/AB^2+1/AC^2=(AB^2+AC^2)/(ABXAC)^2
AB^2+AC^2=BC^2,BCXAD=ABXAC
(AB^2+AC^2)/(ABXAC)^2=BC^2/(BCXAD)^2=1/AD^2
1/AB^2+1/AC^2=(AB^2+AC^2)/(ABXAC)^2=BC^2/(BCXAD)^2=1/AD^2